Saturday, June 23, 2012

2 to go...

Just creating a clean spot in case there is anyone out there who needs to have questions answered over the weekend.

I will check at some point Saturday afternoon and again later in the evening.  I will also check at some point on Sunday and figure I will be on-line a fair amount on Sunday evening as I have to start my report card comments for my other classes anyway.

Mr. A.

3 comments:

  1. Hey sir can I know what you mean about composition of a function problem I couldn't find a problem like that

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  2. You are basically dealing with the chain rule here. A composite function is one that is of the form h(x) = f[g(x)]. So, h'(x) = f'(g(x))*g'(x)

    We also looked at composite functions involving e^x. So, if f(x) = e^[g(x)] which is a composite function, then f'(x) = e^[g(x)]*g'(x) again using chain rule.

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    I also wanted to go back to the problem on page 158. You said for #20 when you solved for the derivative of P(x) you obtained an x-value of 52.5. That is exactly correct. Since x represented the number of $2 increases that means in order to maximize the profit the store would want to increase the price either 52 or 53 times. So, the price would jump to $204 or $206 to obtain max profit.

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