hey sir page 158 #20 i am weak with these questions my P(x)= (120-1x)(100+2x)-(70x) i solved it and i got x= 17.5 which was in my D:[0<x<50] but its wrong in the back of the book
If you let x be the number of $2 increases, you should get the following equation...
P(x) = (100+2x)(120-1x) - 70(120-1x)
Your error was with the cost function. The company only has to pay $70 for each number sold. So, the number sold is the same term as in the revenue function. You are selling 120 at $100 or, (120-1x) depending on the price that is set.
Try the above function and let me know if that works out for you.
hey sir can u tell me that the back of the book is wrong for question 5 on page 114 i got m=26
ReplyDeletehey sir on page 160 #3c i got 2 and 1 as an answer but in the back of the book its 1 i dont know how they got
ReplyDeletesir i am coming to see u tomorrow at 10 is that cool
ReplyDeleteBack of the book is right for #5 on page 114...the slope of the tangent at x=1 is 14.
ReplyDeleteKeep the questions coming and I will respond in a much more timely fashion over the weekend.
Mr. A.
hey sir page 158 #20 i am weak with these questions
ReplyDeletemy P(x)= (120-1x)(100+2x)-(70x)
i solved it and i got x= 17.5 which was in my D:[0<x<50] but its wrong in the back of the book
Recall, Profit = Revenue - Cost, so,
ReplyDeleteP(x) = R(x) - C(x)
If you let x be the number of $2 increases, you should get the following equation...
P(x) = (100+2x)(120-1x) - 70(120-1x)
Your error was with the cost function. The company only has to pay $70 for each number sold. So, the number sold is the same term as in the revenue function. You are selling 120 at $100 or, (120-1x) depending on the price that is set.
Try the above function and let me know if that works out for you.
No it does not work X= 52.5 and when u sub it into p(x) you don't get the same answer
ReplyDelete